Metamath Proof Explorer
Description: 3imp with outermost implication of the hypothesis a biconditional.
(Contributed by Alan Sare, 6-Nov-2017)
|
|
Ref |
Expression |
|
Hypothesis |
bi13imp23.1 |
⊢ ( 𝜑 ↔ ( 𝜓 → ( 𝜒 → 𝜃 ) ) ) |
|
Assertion |
bi13imp23 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
bi13imp23.1 |
⊢ ( 𝜑 ↔ ( 𝜓 → ( 𝜒 → 𝜃 ) ) ) |
2 |
1
|
biimpi |
⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜃 ) ) ) |
3 |
2
|
3imp |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |