Metamath Proof Explorer


Theorem bi23imp1

Description: Similar to 3imp except all but outermost implication are biconditionals. (Contributed by Alan Sare, 6-Nov-2017)

Ref Expression
Hypothesis bi23imp1.1 ( 𝜑 → ( 𝜓 ↔ ( 𝜒𝜃 ) ) )
Assertion bi23imp1 ( ( 𝜑𝜓𝜒 ) → 𝜃 )

Proof

Step Hyp Ref Expression
1 bi23imp1.1 ( 𝜑 → ( 𝜓 ↔ ( 𝜒𝜃 ) ) )
2 biimp ( ( 𝜒𝜃 ) → ( 𝜒𝜃 ) )
3 1 2 syl6bi ( 𝜑 → ( 𝜓 → ( 𝜒𝜃 ) ) )
4 3 3imp ( ( 𝜑𝜓𝜒 ) → 𝜃 )