Metamath Proof Explorer
		
		
		
		Description:  3impib with the inner implication of the hypothesis a biconditional.
       (Contributed by Alan Sare, 6-Nov-2017)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | bi23impib.1 | ⊢ ( 𝜑  →  ( ( 𝜓  ∧  𝜒 )  ↔  𝜃 ) ) | 
				
					|  | Assertion | bi23impib | ⊢  ( ( 𝜑  ∧  𝜓  ∧  𝜒 )  →  𝜃 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | bi23impib.1 | ⊢ ( 𝜑  →  ( ( 𝜓  ∧  𝜒 )  ↔  𝜃 ) ) | 
						
							| 2 | 1 | biimpd | ⊢ ( 𝜑  →  ( ( 𝜓  ∧  𝜒 )  →  𝜃 ) ) | 
						
							| 3 | 2 | 3impib | ⊢ ( ( 𝜑  ∧  𝜓  ∧  𝜒 )  →  𝜃 ) |