Metamath Proof Explorer


Theorem bj-axc16g16

Description: Proof of axc16g from { ax-1 -- ax-7 , axc16 }. (Contributed by BJ, 6-Jul-2021) (Proof modification is discouraged.)

Ref Expression
Assertion bj-axc16g16 ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑧 𝜑 ) )

Proof

Step Hyp Ref Expression
1 aevlem ( ∀ 𝑥 𝑥 = 𝑦 → ∀ 𝑧 𝑧 = 𝑡 )
2 axc16 ( ∀ 𝑧 𝑧 = 𝑡 → ( 𝜑 → ∀ 𝑧 𝜑 ) )
3 1 2 syl ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑧 𝜑 ) )