Metamath Proof Explorer


Theorem bnj1500

Description: Well-founded recursion, part 2 of 3. The proof has been taken from Chapter 4 of Don Monk's notes on Set Theory. See http://euclid.colorado.edu/~monkd/setth.pdf . (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj1500.1 ⊢ 𝐵 = { 𝑑 ∣ ( 𝑑 ⊆ 𝐴 ∧ ∀ 𝑥 ∈ 𝑑 pred ( 𝑥 , 𝐴 , 𝑅 ) ⊆ 𝑑 ) }
bnj1500.2 ⊢ 𝑌 = ⟨ 𝑥 , ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) ⟩
bnj1500.3 ⊢ 𝐶 = { 𝑓 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) }
bnj1500.4 ⊢ 𝐹 = ∪ 𝐶
Assertion bnj1500 ( 𝑅 FrSe 𝐴 → ∀ 𝑥 ∈ 𝐴 ( 𝐹 ‘ 𝑥 ) = ( 𝐺 ‘ ⟨ 𝑥 , ( 𝐹 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) ⟩ ) )

Proof

Step Hyp Ref Expression
1 bnj1500.1 ⊢ 𝐵 = { 𝑑 ∣ ( 𝑑 ⊆ 𝐴 ∧ ∀ 𝑥 ∈ 𝑑 pred ( 𝑥 , 𝐴 , 𝑅 ) ⊆ 𝑑 ) }
2 bnj1500.2 ⊢ 𝑌 = ⟨ 𝑥 , ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) ⟩
3 bnj1500.3 ⊢ 𝐶 = { 𝑓 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) }
4 bnj1500.4 ⊢ 𝐹 = ∪ 𝐶
5 biid ⊢ ( ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) ↔ ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) )
6 biid ⊢ ( ( ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑓 ∈ 𝐶 ∧ 𝑥 ∈ dom 𝑓 ) ↔ ( ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑓 ∈ 𝐶 ∧ 𝑥 ∈ dom 𝑓 ) )
7 biid ⊢ ( ( ( ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑓 ∈ 𝐶 ∧ 𝑥 ∈ dom 𝑓 ) ∧ 𝑑 ∈ 𝐵 ∧ dom 𝑓 = 𝑑 ) ↔ ( ( ( 𝑅 FrSe 𝐴 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑓 ∈ 𝐶 ∧ 𝑥 ∈ dom 𝑓 ) ∧ 𝑑 ∈ 𝐵 ∧ dom 𝑓 = 𝑑 ) )
8 1 2 3 4 5 6 7 bnj1501 ⊢ ( 𝑅 FrSe 𝐴 → ∀ 𝑥 ∈ 𝐴 ( 𝐹 ‘ 𝑥 ) = ( 𝐺 ‘ ⟨ 𝑥 , ( 𝐹 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) ⟩ ) )