Metamath Proof Explorer


Theorem bnj590

Description: Technical lemma for bnj852 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypothesis bnj590.1 ⊢ ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
Assertion bnj590 ( ( 𝐵 = suc 𝑖 ∧ 𝜓 ) → ( 𝑖 ∈ ω → ( 𝐵 ∈ 𝑛 → ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) )

Proof

Step Hyp Ref Expression
1 bnj590.1 ⊢ ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
2 rsp ⊢ ( ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) → ( 𝑖 ∈ ω → ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) )
3 1 2 sylbi ⊢ ( 𝜓 → ( 𝑖 ∈ ω → ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) )
4 eleq1 ⊢ ( 𝐵 = suc 𝑖 → ( 𝐵 ∈ 𝑛 ↔ suc 𝑖 ∈ 𝑛 ) )
5 fveqeq2 ⊢ ( 𝐵 = suc 𝑖 → ( ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ↔ ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
6 4 5 imbi12d ⊢ ( 𝐵 = suc 𝑖 → ( ( 𝐵 ∈ 𝑛 → ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ↔ ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) )
7 6 imbi2d ⊢ ( 𝐵 = suc 𝑖 → ( ( 𝑖 ∈ ω → ( 𝐵 ∈ 𝑛 → ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) ↔ ( 𝑖 ∈ ω → ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) ) )
8 3 7 imbitrrid ⊢ ( 𝐵 = suc 𝑖 → ( 𝜓 → ( 𝑖 ∈ ω → ( 𝐵 ∈ 𝑛 → ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) ) )
9 8 imp ⊢ ( ( 𝐵 = suc 𝑖 ∧ 𝜓 ) → ( 𝑖 ∈ ω → ( 𝐵 ∈ 𝑛 → ( 𝑓 ‘ 𝐵 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) ) )