Description: Distribute conditional equality over equality. (Contributed by Mario Carneiro, 11-Aug-2016)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | cdeqeq.1 | ⊢ CondEq ( 𝑥 = 𝑦 → 𝐴 = 𝐵 ) | |
| cdeqeq.2 | ⊢ CondEq ( 𝑥 = 𝑦 → 𝐶 = 𝐷 ) | ||
| Assertion | cdeqeq | ⊢ CondEq ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cdeqeq.1 | ⊢ CondEq ( 𝑥 = 𝑦 → 𝐴 = 𝐵 ) | |
| 2 | cdeqeq.2 | ⊢ CondEq ( 𝑥 = 𝑦 → 𝐶 = 𝐷 ) | |
| 3 | 1 | cdeqri | ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 ) |
| 4 | 2 | cdeqri | ⊢ ( 𝑥 = 𝑦 → 𝐶 = 𝐷 ) |
| 5 | 3 4 | eqeq12d | ⊢ ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) ) |
| 6 | 5 | cdeqi | ⊢ CondEq ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) ) |