Metamath Proof Explorer


Theorem cdeqeq

Description: Distribute conditional equality over equality. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypotheses cdeqeq.1 ⊢ CondEq ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
cdeqeq.2 ⊢ CondEq ( 𝑥 = 𝑦 → 𝐶 = 𝐷 )
Assertion cdeqeq CondEq ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )

Proof

Step Hyp Ref Expression
1 cdeqeq.1 ⊢ CondEq ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
2 cdeqeq.2 ⊢ CondEq ( 𝑥 = 𝑦 → 𝐶 = 𝐷 )
3 1 cdeqri ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
4 2 cdeqri ⊢ ( 𝑥 = 𝑦 → 𝐶 = 𝐷 )
5 3 4 eqeq12d ⊢ ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )
6 5 cdeqi ⊢ CondEq ( 𝑥 = 𝑦 → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )