Metamath Proof Explorer


Theorem chvarfv

Description: Implicit substitution of y for x into a theorem. Version of chvar with a disjoint variable condition, which does not require ax-13 . (Contributed by Raph Levien, 9-Jul-2003) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses chvarfv.nf 𝑥 𝜓
chvarfv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
chvarfv.2 𝜑
Assertion chvarfv 𝜓

Proof

Step Hyp Ref Expression
1 chvarfv.nf 𝑥 𝜓
2 chvarfv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 chvarfv.2 𝜑
4 2 biimpd ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
5 1 4 spimfv ( ∀ 𝑥 𝜑𝜓 )
6 5 3 mpg 𝜓