Metamath Proof Explorer


Theorem chvarfv

Description: Implicit substitution of y for x into a theorem. Version of chvar with a disjoint variable condition, which does not require ax-13 . (Contributed by Raph Levien, 9-Jul-2003) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses chvarfv.nf ⊢ Ⅎ x ψ
chvarfv.1 ⊢ x = y → φ ↔ ψ
chvarfv.2 ⊢ φ
Assertion chvarfv ⊢ ψ

Proof

Step Hyp Ref Expression
1 chvarfv.nf ⊢ Ⅎ x ψ
2 chvarfv.1 ⊢ x = y → φ ↔ ψ
3 chvarfv.2 ⊢ φ
4 2 biimpd ⊢ x = y → φ → ψ
5 1 4 spimfv ⊢ ∀ x φ → ψ
6 5 3 mpg ⊢ ψ