Metamath Proof Explorer


Theorem coeq1

Description: Equality theorem for composition of two classes. (Contributed by NM, 3-Jan-1997)

Ref Expression
Assertion coeq1 ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 coss1 ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∘ 𝐶 ) ⊆ ( 𝐵 ∘ 𝐶 ) )
2 coss1 ⊢ ( 𝐵 ⊆ 𝐴 → ( 𝐵 ∘ 𝐶 ) ⊆ ( 𝐴 ∘ 𝐶 ) )
3 1 2 anim12i ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) → ( ( 𝐴 ∘ 𝐶 ) ⊆ ( 𝐵 ∘ 𝐶 ) ∧ ( 𝐵 ∘ 𝐶 ) ⊆ ( 𝐴 ∘ 𝐶 ) ) )
4 eqss ⊢ ( 𝐴 = 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) )
5 eqss ⊢ ( ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 ) ↔ ( ( 𝐴 ∘ 𝐶 ) ⊆ ( 𝐵 ∘ 𝐶 ) ∧ ( 𝐵 ∘ 𝐶 ) ⊆ ( 𝐴 ∘ 𝐶 ) ) )
6 3 4 5 3imtr4i ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 ) )