Metamath Proof Explorer


Theorem coss1

Description: Subclass theorem for composition. (Contributed by FL, 30-Dec-2010)

Ref Expression
Assertion coss1 ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∘ 𝐶 ) ⊆ ( 𝐵 ∘ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 ssbr ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑦 𝐴 𝑧 → 𝑦 𝐵 𝑧 ) )
2 1 anim2d ⊢ ( 𝐴 ⊆ 𝐵 → ( ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐴 𝑧 ) → ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐵 𝑧 ) ) )
3 2 eximdv ⊢ ( 𝐴 ⊆ 𝐵 → ( ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐴 𝑧 ) → ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐵 𝑧 ) ) )
4 3 ssopab2dv ⊢ ( 𝐴 ⊆ 𝐵 → { ⟨ 𝑥 , 𝑧 ⟩ ∣ ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐴 𝑧 ) } ⊆ { ⟨ 𝑥 , 𝑧 ⟩ ∣ ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐵 𝑧 ) } )
5 df-co ⊢ ( 𝐴 ∘ 𝐶 ) = { ⟨ 𝑥 , 𝑧 ⟩ ∣ ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐴 𝑧 ) }
6 df-co ⊢ ( 𝐵 ∘ 𝐶 ) = { ⟨ 𝑥 , 𝑧 ⟩ ∣ ∃ 𝑦 ( 𝑥 𝐶 𝑦 ∧ 𝑦 𝐵 𝑧 ) }
7 4 5 6 3sstr4g ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∘ 𝐶 ) ⊆ ( 𝐵 ∘ 𝐶 ) )