Metamath Proof Explorer


Theorem csbco3g

Description: Composition of two class substitutions. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by NM, 27-Nov-2005) (Revised by Mario Carneiro, 11-Nov-2016) (New usage is discouraged.)

Ref Expression
Hypothesis sbcco3g.1 ⊢ ( 𝑥 = 𝐴 → 𝐵 = 𝐶 )
Assertion csbco3g ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ⦋ 𝐵 / 𝑦 ⦌ 𝐷 = ⦋ 𝐶 / 𝑦 ⦌ 𝐷 )

Proof

Step Hyp Ref Expression
1 sbcco3g.1 ⊢ ( 𝑥 = 𝐴 → 𝐵 = 𝐶 )
2 csbnestg ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ⦋ 𝐵 / 𝑦 ⦌ 𝐷 = ⦋ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 / 𝑦 ⦌ 𝐷 )
3 elex ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ∈ V )
4 nfcvd ⊢ ( 𝐴 ∈ V → Ⅎ 𝑥 𝐶 )
5 4 1 csbiegf ⊢ ( 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = 𝐶 )
6 3 5 syl ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = 𝐶 )
7 6 csbeq1d ⊢ ( 𝐴 ∈ 𝑉 → ⦋ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 / 𝑦 ⦌ 𝐷 = ⦋ 𝐶 / 𝑦 ⦌ 𝐷 )
8 2 7 eqtrd ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ⦋ 𝐵 / 𝑦 ⦌ 𝐷 = ⦋ 𝐶 / 𝑦 ⦌ 𝐷 )