Metamath Proof Explorer


Theorem csbconstgi

Description: The proper substitution of a class for a variable in another variable does not modify it, in inference form. (Contributed by Giovanni Mascellani, 30-May-2019)

Ref Expression
Hypothesis csbconstgi.1 𝐴 ∈ V
Assertion csbconstgi 𝐴 / 𝑥 𝑦 = 𝑦

Proof

Step Hyp Ref Expression
1 csbconstgi.1 𝐴 ∈ V
2 csbconstg ( 𝐴 ∈ V → 𝐴 / 𝑥 𝑦 = 𝑦 )
3 1 2 ax-mp 𝐴 / 𝑥 𝑦 = 𝑦