Metamath Proof Explorer


Theorem csbeq2dv

Description: Formula-building deduction for class substitution. (Contributed by NM, 10-Nov-2005) (Revised by Mario Carneiro, 1-Sep-2015)

Ref Expression
Hypothesis csbeq2dv.1 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion csbeq2dv ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )

Proof

Step Hyp Ref Expression
1 csbeq2dv.1 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
2 1 eleq2d ⊢ ( 𝜑 → ( 𝑦 ∈ 𝐵 ↔ 𝑦 ∈ 𝐶 ) )
3 2 sbcbidv ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 ↔ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 ) )
4 3 abbidv ⊢ ( 𝜑 → { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 } = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 } )
5 df-csb ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 }
6 df-csb ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 }
7 4 5 6 3eqtr4g ⊢ ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )