Metamath Proof Explorer


Theorem csbeq2dv

Description: Formula-building deduction for class substitution. (Contributed by NM, 10-Nov-2005) (Revised by Mario Carneiro, 1-Sep-2015)

Ref Expression
Hypothesis csbeq2dv.1 ( 𝜑𝐵 = 𝐶 )
Assertion csbeq2dv ( 𝜑 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐶 )

Proof

Step Hyp Ref Expression
1 csbeq2dv.1 ( 𝜑𝐵 = 𝐶 )
2 nfv 𝑥 𝜑
3 2 1 csbeq2d ( 𝜑 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐶 )