Description: The proper substitution of a proper class for a set into a class results in the empty set. (Contributed by NM, 17-Aug-2018) (Proof shortened by JJ, 27-Aug-2021)
Ref | Expression | ||
---|---|---|---|
Assertion | csbprc | ⊢ ( ¬ 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ∅ ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sbcex | ⊢ ( [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 → 𝐴 ∈ V ) | |
2 | falim | ⊢ ( ⊥ → 𝐴 ∈ V ) | |
3 | 1 2 | pm5.21ni | ⊢ ( ¬ 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 ↔ ⊥ ) ) |
4 | 3 | abbidv | ⊢ ( ¬ 𝐴 ∈ V → { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 } = { 𝑦 ∣ ⊥ } ) |
5 | df-csb | ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 } | |
6 | fal | ⊢ ¬ ⊥ | |
7 | 6 | abf | ⊢ { 𝑦 ∣ ⊥ } = ∅ |
8 | 7 | eqcomi | ⊢ ∅ = { 𝑦 ∣ ⊥ } |
9 | 4 5 8 | 3eqtr4g | ⊢ ( ¬ 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ∅ ) |