Metamath Proof Explorer


Theorem cyclispth

Description: A cycle is a path. (Contributed by Alexander van der Vekens, 30-Oct-2017) (Revised by AV, 31-Jan-2021)

Ref Expression
Assertion cyclispth ( 𝐹 ( Cycles ‘ 𝐺 ) 𝑃𝐹 ( Paths ‘ 𝐺 ) 𝑃 )

Proof

Step Hyp Ref Expression
1 cyclprop ( 𝐹 ( Cycles ‘ 𝐺 ) 𝑃 → ( 𝐹 ( Paths ‘ 𝐺 ) 𝑃 ∧ ( 𝑃 ‘ 0 ) = ( 𝑃 ‘ ( ♯ ‘ 𝐹 ) ) ) )
2 1 simpld ( 𝐹 ( Cycles ‘ 𝐺 ) 𝑃𝐹 ( Paths ‘ 𝐺 ) 𝑃 )