Metamath Proof Explorer


Definition df-homf

Description: Define the functionalized Hom-set operator, which is exactly like Hom but is guaranteed to be a function on the base. (Contributed by Mario Carneiro, 4-Jan-2017)

Ref Expression
Assertion df-homf Homf = ( 𝑐 ∈ V ↦ ( 𝑥 ∈ ( Base ‘ 𝑐 ) , 𝑦 ∈ ( Base ‘ 𝑐 ) ↦ ( 𝑥 ( Hom ‘ 𝑐 ) 𝑦 ) ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 chomf ⊢ Homf
1 vc ⊢ 𝑐
2 cvv ⊢ V
3 vx ⊢ 𝑥
4 cbs ⊢ Base
5 1 cv ⊢ 𝑐
6 5 4 cfv ⊢ ( Base ‘ 𝑐 )
7 vy ⊢ 𝑦
8 3 cv ⊢ 𝑥
9 chom ⊢ Hom
10 5 9 cfv ⊢ ( Hom ‘ 𝑐 )
11 7 cv ⊢ 𝑦
12 8 11 10 co ⊢ ( 𝑥 ( Hom ‘ 𝑐 ) 𝑦 )
13 3 7 6 6 12 cmpo ⊢ ( 𝑥 ∈ ( Base ‘ 𝑐 ) , 𝑦 ∈ ( Base ‘ 𝑐 ) ↦ ( 𝑥 ( Hom ‘ 𝑐 ) 𝑦 ) )
14 1 2 13 cmpt ⊢ ( 𝑐 ∈ V ↦ ( 𝑥 ∈ ( Base ‘ 𝑐 ) , 𝑦 ∈ ( Base ‘ 𝑐 ) ↦ ( 𝑥 ( Hom ‘ 𝑐 ) 𝑦 ) ) )
15 0 14 wceq ⊢ Homf = ( 𝑐 ∈ V ↦ ( 𝑥 ∈ ( Base ‘ 𝑐 ) , 𝑦 ∈ ( Base ‘ 𝑐 ) ↦ ( 𝑥 ( Hom ‘ 𝑐 ) 𝑦 ) ) )