Metamath Proof Explorer


Definition df-k3

Description: Define a function that takes an ordinal and returns the third argument of the ordered triple <. x , y , n >. such that the ordinal equals ( J<. x , y , n >. ) . Based on the third case of Definition 15.7 of TakeutiZaring p. 156. (Contributed by BTernaryTau, 2-Sep-2026)

Ref Expression
Assertion df-k3 𝐾3 = { ⟨ 𝑧 , 𝑛 ⟩ ∣ ( 𝑛 ∈ 9o ∧ ∃ 𝑥 ∈ On ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ ) ) }

Detailed syntax breakdown

Step Hyp Ref Expression
0 ck3 ⊢ 𝐾3
1 vz ⊢ 𝑧
2 vn ⊢ 𝑛
3 2 cv ⊢ 𝑛
4 c9o ⊢ 9o
5 3 4 wcel ⊢ 𝑛 ∈ 9o
6 vx ⊢ 𝑥
7 con0 ⊢ On
8 vy ⊢ 𝑦
9 1 cv ⊢ 𝑧
10 cj ⊢ 𝐽
11 6 cv ⊢ 𝑥
12 8 cv ⊢ 𝑦
13 11 12 3 cotp ⊢ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩
14 13 10 cfv ⊢ ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ )
15 9 14 wceq ⊢ 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ )
16 15 8 7 wrex ⊢ ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ )
17 16 6 7 wrex ⊢ ∃ 𝑥 ∈ On ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ )
18 5 17 wa ⊢ ( 𝑛 ∈ 9o ∧ ∃ 𝑥 ∈ On ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ ) )
19 18 1 2 copab ⊢ { ⟨ 𝑧 , 𝑛 ⟩ ∣ ( 𝑛 ∈ 9o ∧ ∃ 𝑥 ∈ On ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ ) ) }
20 0 19 wceq ⊢ 𝐾3 = { ⟨ 𝑧 , 𝑛 ⟩ ∣ ( 𝑛 ∈ 9o ∧ ∃ 𝑥 ∈ On ∃ 𝑦 ∈ On 𝑧 = ( 𝐽 ‘ ⟨ 𝑥 , 𝑦 , 𝑛 ⟩ ) ) }