Metamath Proof Explorer


Theorem dfin5

Description: Alternate definition for the intersection of two classes. (Contributed by NM, 6-Jul-2005)

Ref Expression
Assertion dfin5 ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵 }

Proof

Step Hyp Ref Expression
1 df-in ⊢ ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵 ) }
2 df-rab ⊢ { 𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵 } = { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵 ) }
3 1 2 eqtr4i ⊢ ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵 }