Metamath Proof Explorer


Theorem dfss3f

Description: Equivalence for subclass relation, using bound-variable hypotheses instead of distinct variable conditions. (Contributed by NM, 20-Mar-2004)

Ref Expression
Hypotheses dfssf.1 ⊢ Ⅎ 𝑥 𝐴
dfssf.2 ⊢ Ⅎ 𝑥 𝐵
Assertion dfss3f ( 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 𝑥 ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 dfssf.1 ⊢ Ⅎ 𝑥 𝐴
2 dfssf.2 ⊢ Ⅎ 𝑥 𝐵
3 1 2 dfssf ⊢ ( 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
4 df-ral ⊢ ( ∀ 𝑥 ∈ 𝐴 𝑥 ∈ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
5 3 4 bitr4i ⊢ ( 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 𝑥 ∈ 𝐵 )