Metamath Proof Explorer


Theorem difeq12

Description: Equality theorem for class difference. (Contributed by FL, 31-Aug-2009)

Ref Expression
Assertion difeq12 ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐷 ) )

Proof

Step Hyp Ref Expression
1 difeq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐶 ) )
2 difeq2 ⊢ ( 𝐶 = 𝐷 → ( 𝐵 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐷 ) )
3 1 2 sylan9eq ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 ∖ 𝐶 ) = ( 𝐵 ∖ 𝐷 ) )