Metamath Proof Explorer


Theorem dmeq

Description: Equality theorem for domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion dmeq ( 𝐴 = 𝐵 → dom 𝐴 = dom 𝐵 )

Proof

Step Hyp Ref Expression
1 dmss ⊢ ( 𝐴 ⊆ 𝐵 → dom 𝐴 ⊆ dom 𝐵 )
2 dmss ⊢ ( 𝐵 ⊆ 𝐴 → dom 𝐵 ⊆ dom 𝐴 )
3 1 2 anim12i ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) → ( dom 𝐴 ⊆ dom 𝐵 ∧ dom 𝐵 ⊆ dom 𝐴 ) )
4 eqss ⊢ ( 𝐴 = 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) )
5 eqss ⊢ ( dom 𝐴 = dom 𝐵 ↔ ( dom 𝐴 ⊆ dom 𝐵 ∧ dom 𝐵 ⊆ dom 𝐴 ) )
6 3 4 5 3imtr4i ⊢ ( 𝐴 = 𝐵 → dom 𝐴 = dom 𝐵 )