Metamath Proof Explorer


Theorem dmeq

Description: Equality theorem for domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion dmeq ⊢ A = B → dom ⁡ A = dom ⁡ B

Proof

Step Hyp Ref Expression
1 dmss ⊢ A ⊆ B → dom ⁡ A ⊆ dom ⁡ B
2 dmss ⊢ B ⊆ A → dom ⁡ B ⊆ dom ⁡ A
3 1 2 anim12i ⊢ A ⊆ B ∧ B ⊆ A → dom ⁡ A ⊆ dom ⁡ B ∧ dom ⁡ B ⊆ dom ⁡ A
4 eqss ⊢ A = B ↔ A ⊆ B ∧ B ⊆ A
5 eqss ⊢ dom ⁡ A = dom ⁡ B ↔ dom ⁡ A ⊆ dom ⁡ B ∧ dom ⁡ B ⊆ dom ⁡ A
6 3 4 5 3imtr4i ⊢ A = B → dom ⁡ A = dom ⁡ B