Metamath Proof Explorer


Theorem ecref

Description: All elements are in their own equivalence class. (Contributed by Thierry Arnoux, 14-Feb-2025)

Ref Expression
Assertion ecref ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → 𝐴 ∈ [ 𝐴 ] 𝑅 )

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → 𝑅 Er 𝑋 )
2 simpr ⊢ ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → 𝐴 ∈ 𝑋 )
3 1 2 erref ⊢ ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → 𝐴 𝑅 𝐴 )
4 elecg ⊢ ( ( 𝐴 ∈ 𝑋 ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 ∈ [ 𝐴 ] 𝑅 ↔ 𝐴 𝑅 𝐴 ) )
5 2 4 sylancom ⊢ ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 ∈ [ 𝐴 ] 𝑅 ↔ 𝐴 𝑅 𝐴 ) )
6 3 5 mpbird ⊢ ( ( 𝑅 Er 𝑋 ∧ 𝐴 ∈ 𝑋 ) → 𝐴 ∈ [ 𝐴 ] 𝑅 )