Metamath Proof Explorer


Theorem eleq1i

Description: Inference from equality to equivalence of membership. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypothesis eleq1i.1 𝐴 = 𝐵
Assertion eleq1i ( 𝐴𝐶𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 eleq1i.1 𝐴 = 𝐵
2 eleq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶𝐵𝐶 ) )
3 1 2 ax-mp ( 𝐴𝐶𝐵𝐶 )