Metamath Proof Explorer


Theorem eliminable-velab

Description: A theorem used to prove the base case of the Eliminability Theorem (see section comment): variable belongs to abstraction. (Contributed by BJ, 30-Apr-2024) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion eliminable-velab ( 𝑦 ∈ { 𝑥𝜑 } ↔ [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 df-clab ( 𝑦 ∈ { 𝑥𝜑 } ↔ [ 𝑦 / 𝑥 ] 𝜑 )