Metamath Proof Explorer


Theorem eliminable2b

Description: A theorem used to prove the base case of the Eliminability Theorem (see section comment). (Contributed by BJ, 19-Oct-2019) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion eliminable2b ( { 𝑥 ∣ 𝜑 } = 𝑦 ↔ ∀ 𝑧 ( 𝑧 ∈ { 𝑥 ∣ 𝜑 } ↔ 𝑧 ∈ 𝑦 ) )

Proof

Step Hyp Ref Expression
1 dfcleq ⊢ ( { 𝑥 ∣ 𝜑 } = 𝑦 ↔ ∀ 𝑧 ( 𝑧 ∈ { 𝑥 ∣ 𝜑 } ↔ 𝑧 ∈ 𝑦 ) )