Metamath Proof Explorer
Description: There is exactly one element in a singleton. Exercise 2 of
TakeutiZaring p. 15. (Contributed by NM, 13-Sep-1995)
|
|
Ref |
Expression |
|
Hypothesis |
elsn.1 |
⊢ 𝐴 ∈ V |
|
Assertion |
elsn |
⊢ ( 𝐴 ∈ { 𝐵 } ↔ 𝐴 = 𝐵 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
elsn.1 |
⊢ 𝐴 ∈ V |
| 2 |
|
elsng |
⊢ ( 𝐴 ∈ V → ( 𝐴 ∈ { 𝐵 } ↔ 𝐴 = 𝐵 ) ) |
| 3 |
1 2
|
ax-mp |
⊢ ( 𝐴 ∈ { 𝐵 } ↔ 𝐴 = 𝐵 ) |