Metamath Proof Explorer


Theorem elspancl

Description: A member of a span is a vector. (Contributed by NM, 17-Dec-2004) (New usage is discouraged.)

Ref Expression
Assertion elspancl ( ( 𝐴 ⊆ ℋ ∧ 𝐵 ∈ ( span ‘ 𝐴 ) ) → 𝐵 ∈ ℋ )

Proof

Step Hyp Ref Expression
1 spancl ⊢ ( 𝐴 ⊆ ℋ → ( span ‘ 𝐴 ) ∈ Sℋ )
2 shel ⊢ ( ( ( span ‘ 𝐴 ) ∈ Sℋ ∧ 𝐵 ∈ ( span ‘ 𝐴 ) ) → 𝐵 ∈ ℋ )
3 1 2 sylan ⊢ ( ( 𝐴 ⊆ ℋ ∧ 𝐵 ∈ ( span ‘ 𝐴 ) ) → 𝐵 ∈ ℋ )