Metamath Proof Explorer


Theorem eqeqan12dALT

Description: Alternate proof of eqeqan12d . This proof has one more step but one fewer essential step. (Contributed by NM, 9-Aug-1994) (Proof shortened by Andrew Salmon, 25-May-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses eqeqan12dALT.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
eqeqan12dALT.2 ⊢ ( 𝜓 → 𝐶 = 𝐷 )
Assertion eqeqan12dALT ( ( 𝜑 ∧ 𝜓 ) → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )

Proof

Step Hyp Ref Expression
1 eqeqan12dALT.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 eqeqan12dALT.2 ⊢ ( 𝜓 → 𝐶 = 𝐷 )
3 eqeq12 ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )
4 1 2 3 syl2an ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )