Metamath Proof Explorer


Theorem eqtr2d

Description: An equality transitivity deduction. (Contributed by NM, 18-Oct-1999)

Ref Expression
Hypotheses eqtr2d.1 ( 𝜑𝐴 = 𝐵 )
eqtr2d.2 ( 𝜑𝐵 = 𝐶 )
Assertion eqtr2d ( 𝜑𝐶 = 𝐴 )

Proof

Step Hyp Ref Expression
1 eqtr2d.1 ( 𝜑𝐴 = 𝐵 )
2 eqtr2d.2 ( 𝜑𝐵 = 𝐶 )
3 1 2 eqtrd ( 𝜑𝐴 = 𝐶 )
4 3 eqcomd ( 𝜑𝐶 = 𝐴 )