Metamath Proof Explorer


Theorem exel

Description: There exist two sets, one a member of the other.

This theorem looks similar to el , but its meaning is different. It only depends on the axioms ax-mp to ax-4 , ax-6 , and ax-pr . This theorem does not exclude that these two sets could actually be one single set containing itself. That two different sets exist is proved by exexneq . (Contributed by SN, 23-Dec-2024)

Ref Expression
Assertion exel ∃ 𝑦 ∃ 𝑥 𝑥 ∈ 𝑦

Proof

Step Hyp Ref Expression
1 ax-pr ⊢ ∃ 𝑦 ∀ 𝑥 ( ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 ) → 𝑥 ∈ 𝑦 )
2 ax6ev ⊢ ∃ 𝑥 𝑥 = 𝑧
3 pm2.07 ⊢ ( 𝑥 = 𝑧 → ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 ) )
4 2 3 eximii ⊢ ∃ 𝑥 ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 )
5 exim ⊢ ( ∀ 𝑥 ( ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 ) → 𝑥 ∈ 𝑦 ) → ( ∃ 𝑥 ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 ) → ∃ 𝑥 𝑥 ∈ 𝑦 ) )
6 4 5 mpi ⊢ ( ∀ 𝑥 ( ( 𝑥 = 𝑧 ∨ 𝑥 = 𝑧 ) → 𝑥 ∈ 𝑦 ) → ∃ 𝑥 𝑥 ∈ 𝑦 )
7 1 6 eximii ⊢ ∃ 𝑦 ∃ 𝑥 𝑥 ∈ 𝑦