Metamath Proof Explorer
Description: Introduce a conjunct in the scope of an existential quantifier.
(Contributed by NM, 11-Aug-1993) (Proof shortened by BJ, 16-Sep-2022)
|
|
Ref |
Expression |
|
Assertion |
exintr |
⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) → ( ∃ 𝑥 𝜑 → ∃ 𝑥 ( 𝜑 ∧ 𝜓 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ancl |
⊢ ( ( 𝜑 → 𝜓 ) → ( 𝜑 → ( 𝜑 ∧ 𝜓 ) ) ) |
2 |
1
|
aleximi |
⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) → ( ∃ 𝑥 𝜑 → ∃ 𝑥 ( 𝜑 ∧ 𝜓 ) ) ) |