Metamath Proof Explorer


Theorem expi

Description: An exportation inference. (Contributed by NM, 29-Dec-1992) (Proof shortened by Mel L. O'Cat, 28-Nov-2008)

Ref Expression
Hypothesis expi.1 ( ¬ ( 𝜑 → ¬ 𝜓 ) → 𝜒 )
Assertion expi ( 𝜑 → ( 𝜓𝜒 ) )

Proof

Step Hyp Ref Expression
1 expi.1 ( ¬ ( 𝜑 → ¬ 𝜓 ) → 𝜒 )
2 pm3.2im ( 𝜑 → ( 𝜓 → ¬ ( 𝜑 → ¬ 𝜓 ) ) )
3 2 1 syl6 ( 𝜑 → ( 𝜓𝜒 ) )