Metamath Proof Explorer


Theorem exsbim

Description: One direction of the equivalence in exsb is based on fewer axioms. (Contributed by Wolf Lammen, 2-Mar-2023)

Ref Expression
Assertion exsbim ( ∃ 𝑦 ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → ∃ 𝑥 𝜑 )

Proof

Step Hyp Ref Expression
1 alequexv ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → ∃ 𝑥 𝜑 )
2 1 exlimiv ⊢ ( ∃ 𝑦 ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → ∃ 𝑥 𝜑 )