Metamath Proof Explorer


Theorem exsb

Description: An equivalent expression for existence. One direction ( exsbim ) needs fewer axioms. (Contributed by NM, 2-Feb-2005) Avoid ax-13 . (Revised by Wolf Lammen, 16-Oct-2022)

Ref Expression
Assertion exsb ( ∃ 𝑥 𝜑 ↔ ∃ 𝑦 ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) )

Proof

Step Hyp Ref Expression
1 nfv ⊢ Ⅎ 𝑦 𝜑
2 nfa1 ⊢ Ⅎ 𝑥 ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 )
3 ax12v ⊢ ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ) )
4 sp ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → ( 𝑥 = 𝑦 → 𝜑 ) )
5 4 com12 ⊢ ( 𝑥 = 𝑦 → ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → 𝜑 ) )
6 3 5 impbid ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ) )
7 1 2 6 cbvexv1 ⊢ ( ∃ 𝑥 𝜑 ↔ ∃ 𝑦 ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) )