Metamath Proof Explorer


Theorem ffn

Description: A mapping is a function with domain. (Contributed by NM, 2-Aug-1994)

Ref Expression
Assertion ffn ( 𝐹 : 𝐴 ⟶ 𝐵 → 𝐹 Fn 𝐴 )

Proof

Step Hyp Ref Expression
1 df-f ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) )
2 1 simplbi ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 → 𝐹 Fn 𝐴 )