Metamath Proof Explorer


Theorem fnbr

Description: The first argument of binary relation on a function belongs to the function's domain. (Contributed by NM, 7-May-2004)

Ref Expression
Assertion fnbr ( ( 𝐹 Fn 𝐴𝐵 𝐹 𝐶 ) → 𝐵𝐴 )

Proof

Step Hyp Ref Expression
1 fnrel ( 𝐹 Fn 𝐴 → Rel 𝐹 )
2 releldm ( ( Rel 𝐹𝐵 𝐹 𝐶 ) → 𝐵 ∈ dom 𝐹 )
3 1 2 sylan ( ( 𝐹 Fn 𝐴𝐵 𝐹 𝐶 ) → 𝐵 ∈ dom 𝐹 )
4 fndm ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 )
5 4 eleq2d ( 𝐹 Fn 𝐴 → ( 𝐵 ∈ dom 𝐹𝐵𝐴 ) )
6 5 biimpa ( ( 𝐹 Fn 𝐴𝐵 ∈ dom 𝐹 ) → 𝐵𝐴 )
7 3 6 syldan ( ( 𝐹 Fn 𝐴𝐵 𝐹 𝐶 ) → 𝐵𝐴 )