Metamath Proof Explorer


Theorem fnbr

Description: The first argument of binary relation on a function belongs to the function's domain. (Contributed by NM, 7-May-2004)

Ref Expression
Assertion fnbr ( ( 𝐹 Fn 𝐴 ∧ 𝐵 𝐹 𝐶 ) → 𝐵 ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 fnrel ⊢ ( 𝐹 Fn 𝐴 → Rel 𝐹 )
2 releldm ⊢ ( ( Rel 𝐹 ∧ 𝐵 𝐹 𝐶 ) → 𝐵 ∈ dom 𝐹 )
3 1 2 sylan ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 𝐹 𝐶 ) → 𝐵 ∈ dom 𝐹 )
4 fndm ⊢ ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 )
5 4 eleq2d ⊢ ( 𝐹 Fn 𝐴 → ( 𝐵 ∈ dom 𝐹 ↔ 𝐵 ∈ 𝐴 ) )
6 5 biimpa ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ∈ dom 𝐹 ) → 𝐵 ∈ 𝐴 )
7 3 6 syldan ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 𝐹 𝐶 ) → 𝐵 ∈ 𝐴 )