Metamath Proof Explorer


Theorem fndmd

Description: The domain of a function. (Contributed by Glauco Siliprandi, 23-Oct-2021)

Ref Expression
Hypothesis fndmd.1 ( 𝜑𝐹 Fn 𝐴 )
Assertion fndmd ( 𝜑 → dom 𝐹 = 𝐴 )

Proof

Step Hyp Ref Expression
1 fndmd.1 ( 𝜑𝐹 Fn 𝐴 )
2 fndm ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 )
3 1 2 syl ( 𝜑 → dom 𝐹 = 𝐴 )