Metamath Proof Explorer


Theorem fndmd

Description: The domain of a function. (Contributed by Glauco Siliprandi, 23-Oct-2021)

Ref Expression
Hypothesis fndmd.1 ⊢ φ → F Fn A
Assertion fndmd ⊢ φ → dom ⁡ F = A

Proof

Step Hyp Ref Expression
1 fndmd.1 ⊢ φ → F Fn A
2 fndm ⊢ F Fn A → dom ⁡ F = A
3 1 2 syl ⊢ φ → dom ⁡ F = A