Metamath Proof Explorer


Theorem fnunirn

Description: Membership in a union of some function-defined family of sets. (Contributed by Stefan O'Rear, 30-Jan-2015)

Ref Expression
Assertion fnunirn ( 𝐹 Fn 𝐼 → ( 𝐴 ran 𝐹 ↔ ∃ 𝑥𝐼 𝐴 ∈ ( 𝐹𝑥 ) ) )

Proof

Step Hyp Ref Expression
1 fnfun ( 𝐹 Fn 𝐼 → Fun 𝐹 )
2 elunirn ( Fun 𝐹 → ( 𝐴 ran 𝐹 ↔ ∃ 𝑥 ∈ dom 𝐹 𝐴 ∈ ( 𝐹𝑥 ) ) )
3 1 2 syl ( 𝐹 Fn 𝐼 → ( 𝐴 ran 𝐹 ↔ ∃ 𝑥 ∈ dom 𝐹 𝐴 ∈ ( 𝐹𝑥 ) ) )
4 fndm ( 𝐹 Fn 𝐼 → dom 𝐹 = 𝐼 )
5 4 rexeqdv ( 𝐹 Fn 𝐼 → ( ∃ 𝑥 ∈ dom 𝐹 𝐴 ∈ ( 𝐹𝑥 ) ↔ ∃ 𝑥𝐼 𝐴 ∈ ( 𝐹𝑥 ) ) )
6 3 5 bitrd ( 𝐹 Fn 𝐼 → ( 𝐴 ran 𝐹 ↔ ∃ 𝑥𝐼 𝐴 ∈ ( 𝐹𝑥 ) ) )