Metamath Proof Explorer


Theorem rexeqdv

Description: Equality deduction for restricted existential quantifier. (Contributed by NM, 14-Jan-2007)

Ref Expression
Hypothesis raleqdv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion rexeqdv ( 𝜑 → ( ∃ 𝑥 ∈ 𝐴 𝜓 ↔ ∃ 𝑥 ∈ 𝐵 𝜓 ) )

Proof

Step Hyp Ref Expression
1 raleqdv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 rexeq ⊢ ( 𝐴 = 𝐵 → ( ∃ 𝑥 ∈ 𝐴 𝜓 ↔ ∃ 𝑥 ∈ 𝐵 𝜓 ) )
3 1 2 syl ⊢ ( 𝜑 → ( ∃ 𝑥 ∈ 𝐴 𝜓 ↔ ∃ 𝑥 ∈ 𝐵 𝜓 ) )