| Step | 
						Hyp | 
						Ref | 
						Expression | 
					
						
							| 1 | 
							
								
							 | 
							fndm | 
							⊢ ( 𝐹  Fn  𝐴  →  dom  𝐹  =  𝐴 )  | 
						
						
							| 2 | 
							
								1
							 | 
							3ad2ant1 | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  dom  𝐹  =  𝐴 )  | 
						
						
							| 3 | 
							
								2
							 | 
							reseq2d | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( ( 𝐹  ∪  𝐺 )  ↾  dom  𝐹 )  =  ( ( 𝐹  ∪  𝐺 )  ↾  𝐴 ) )  | 
						
						
							| 4 | 
							
								
							 | 
							fnrel | 
							⊢ ( 𝐹  Fn  𝐴  →  Rel  𝐹 )  | 
						
						
							| 5 | 
							
								4
							 | 
							3ad2ant1 | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  Rel  𝐹 )  | 
						
						
							| 6 | 
							
								
							 | 
							fndm | 
							⊢ ( 𝐺  Fn  𝐵  →  dom  𝐺  =  𝐵 )  | 
						
						
							| 7 | 
							
								6
							 | 
							3ad2ant2 | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  dom  𝐺  =  𝐵 )  | 
						
						
							| 8 | 
							
								2 7
							 | 
							ineq12d | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( dom  𝐹  ∩  dom  𝐺 )  =  ( 𝐴  ∩  𝐵 ) )  | 
						
						
							| 9 | 
							
								
							 | 
							simp3 | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( 𝐴  ∩  𝐵 )  =  ∅ )  | 
						
						
							| 10 | 
							
								8 9
							 | 
							eqtrd | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( dom  𝐹  ∩  dom  𝐺 )  =  ∅ )  | 
						
						
							| 11 | 
							
								
							 | 
							relresdm1 | 
							⊢ ( ( Rel  𝐹  ∧  ( dom  𝐹  ∩  dom  𝐺 )  =  ∅ )  →  ( ( 𝐹  ∪  𝐺 )  ↾  dom  𝐹 )  =  𝐹 )  | 
						
						
							| 12 | 
							
								5 10 11
							 | 
							syl2anc | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( ( 𝐹  ∪  𝐺 )  ↾  dom  𝐹 )  =  𝐹 )  | 
						
						
							| 13 | 
							
								3 12
							 | 
							eqtr3d | 
							⊢ ( ( 𝐹  Fn  𝐴  ∧  𝐺  Fn  𝐵  ∧  ( 𝐴  ∩  𝐵 )  =  ∅ )  →  ( ( 𝐹  ∪  𝐺 )  ↾  𝐴 )  =  𝐹 )  |