Metamath Proof Explorer


Theorem fpmg

Description: A total function is a partial function. (Contributed by Mario Carneiro, 31-Dec-2013)

Ref Expression
Assertion fpmg ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 ∈ ( 𝐵 ↑pm 𝐴 ) )

Proof

Step Hyp Ref Expression
1 ssid ⊢ 𝐴 ⊆ 𝐴
2 elpm2r ⊢ ( ( ( 𝐵 ∈ 𝑊 ∧ 𝐴 ∈ 𝑉 ) ∧ ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝐴 ⊆ 𝐴 ) ) → 𝐹 ∈ ( 𝐵 ↑pm 𝐴 ) )
3 1 2 mpanr2 ⊢ ( ( ( 𝐵 ∈ 𝑊 ∧ 𝐴 ∈ 𝑉 ) ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 ∈ ( 𝐵 ↑pm 𝐴 ) )
4 3 3impa ⊢ ( ( 𝐵 ∈ 𝑊 ∧ 𝐴 ∈ 𝑉 ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 ∈ ( 𝐵 ↑pm 𝐴 ) )
5 4 3com12 ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 ∈ ( 𝐵 ↑pm 𝐴 ) )