Metamath Proof Explorer


Theorem frege87

Description: If Z is a result of an application of the procedure R to an object Y that follows X in the R -sequence and if every result of an application of the procedure R to X has a property A that is hereditary in the R -sequence, then Z has property A . Proposition 87 of Frege1879 p. 66. (Contributed by RP, 1-Jul-2020) (Revised by RP, 7-Jul-2020) (Proof modification is discouraged.)

Ref Expression
Hypotheses frege87.x ⊢ 𝑋 ∈ 𝑈
frege87.y ⊢ 𝑌 ∈ 𝑉
frege87.z ⊢ 𝑍 ∈ 𝑊
frege87.r ⊢ 𝑅 ∈ 𝑆
frege87.a ⊢ 𝐴 ∈ 𝐵
Assertion frege87 ( 𝑋 ( t+ ‘ 𝑅 ) 𝑌 → ( ∀ 𝑤 ( 𝑋 𝑅 𝑤 → 𝑤 ∈ 𝐴 ) → ( 𝑅 hereditary 𝐴 → ( 𝑌 𝑅 𝑍 → 𝑍 ∈ 𝐴 ) ) ) )

Proof

Step Hyp Ref Expression
1 frege87.x ⊢ 𝑋 ∈ 𝑈
2 frege87.y ⊢ 𝑌 ∈ 𝑉
3 frege87.z ⊢ 𝑍 ∈ 𝑊
4 frege87.r ⊢ 𝑅 ∈ 𝑆
5 frege87.a ⊢ 𝐴 ∈ 𝐵
6 2 3 frege73 ⊢ ( ( 𝑅 hereditary 𝐴 → 𝑌 ∈ 𝐴 ) → ( 𝑅 hereditary 𝐴 → ( 𝑌 𝑅 𝑍 → 𝑍 ∈ 𝐴 ) ) )
7 1 2 4 5 frege86 ⊢ ( ( ( 𝑅 hereditary 𝐴 → 𝑌 ∈ 𝐴 ) → ( 𝑅 hereditary 𝐴 → ( 𝑌 𝑅 𝑍 → 𝑍 ∈ 𝐴 ) ) ) → ( 𝑋 ( t+ ‘ 𝑅 ) 𝑌 → ( ∀ 𝑤 ( 𝑋 𝑅 𝑤 → 𝑤 ∈ 𝐴 ) → ( 𝑅 hereditary 𝐴 → ( 𝑌 𝑅 𝑍 → 𝑍 ∈ 𝐴 ) ) ) ) )
8 6 7 ax-mp ⊢ ( 𝑋 ( t+ ‘ 𝑅 ) 𝑌 → ( ∀ 𝑤 ( 𝑋 𝑅 𝑤 → 𝑤 ∈ 𝐴 ) → ( 𝑅 hereditary 𝐴 → ( 𝑌 𝑅 𝑍 → 𝑍 ∈ 𝐴 ) ) ) )