Metamath Proof Explorer


Theorem fundmeng

Description: A function is equinumerous to its domain. Exercise 4 of Suppes p. 98. (Contributed by NM, 17-Sep-2013)

Ref Expression
Assertion fundmeng ( ( 𝐹 ∈ 𝑉 ∧ Fun 𝐹 ) → dom 𝐹 ≈ 𝐹 )

Proof

Step Hyp Ref Expression
1 funeq ⊢ ( 𝑥 = 𝐹 → ( Fun 𝑥 ↔ Fun 𝐹 ) )
2 dmeq ⊢ ( 𝑥 = 𝐹 → dom 𝑥 = dom 𝐹 )
3 id ⊢ ( 𝑥 = 𝐹 → 𝑥 = 𝐹 )
4 2 3 breq12d ⊢ ( 𝑥 = 𝐹 → ( dom 𝑥 ≈ 𝑥 ↔ dom 𝐹 ≈ 𝐹 ) )
5 1 4 imbi12d ⊢ ( 𝑥 = 𝐹 → ( ( Fun 𝑥 → dom 𝑥 ≈ 𝑥 ) ↔ ( Fun 𝐹 → dom 𝐹 ≈ 𝐹 ) ) )
6 vex ⊢ 𝑥 ∈ V
7 6 fundmen ⊢ ( Fun 𝑥 → dom 𝑥 ≈ 𝑥 )
8 5 7 vtoclg ⊢ ( 𝐹 ∈ 𝑉 → ( Fun 𝐹 → dom 𝐹 ≈ 𝐹 ) )
9 8 imp ⊢ ( ( 𝐹 ∈ 𝑉 ∧ Fun 𝐹 ) → dom 𝐹 ≈ 𝐹 )