Metamath Proof Explorer


Theorem fununfun

Description: If the union of classes is a function, the classes themselves are functions. (Contributed by AV, 18-Jul-2019) Shorten proof and remove dependency on ax-sep and ax-pr . (Revised by Eric Schmidt, 24-Oct-2026)

Ref Expression
Assertion fununfun ( Fun ( 𝐹 ∪ 𝐺 ) → ( Fun 𝐹 ∧ Fun 𝐺 ) )

Proof

Step Hyp Ref Expression
1 ssun1 ⊢ 𝐹 ⊆ ( 𝐹 ∪ 𝐺 )
2 funss ⊢ ( 𝐹 ⊆ ( 𝐹 ∪ 𝐺 ) → ( Fun ( 𝐹 ∪ 𝐺 ) → Fun 𝐹 ) )
3 1 2 ax-mp ⊢ ( Fun ( 𝐹 ∪ 𝐺 ) → Fun 𝐹 )
4 ssun2 ⊢ 𝐺 ⊆ ( 𝐹 ∪ 𝐺 )
5 funss ⊢ ( 𝐺 ⊆ ( 𝐹 ∪ 𝐺 ) → ( Fun ( 𝐹 ∪ 𝐺 ) → Fun 𝐺 ) )
6 4 5 ax-mp ⊢ ( Fun ( 𝐹 ∪ 𝐺 ) → Fun 𝐺 )
7 3 6 jca ⊢ ( Fun ( 𝐹 ∪ 𝐺 ) → ( Fun 𝐹 ∧ Fun 𝐺 ) )