Metamath Proof Explorer
Description: Deduction version of fvmpt (where the substitution hypothesis does not
have the antecedent ph ). (Contributed by SN, 26-Jul-2024)
|
|
Ref |
Expression |
|
Hypotheses |
fvmptd4.1 |
⊢ ( 𝑥 = 𝐴 → 𝐵 = 𝐶 ) |
|
|
fvmptd4.2 |
⊢ ( 𝜑 → 𝐹 = ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) |
|
|
fvmptd4.3 |
⊢ ( 𝜑 → 𝐴 ∈ 𝐷 ) |
|
|
fvmptd4.4 |
⊢ ( 𝜑 → 𝐶 ∈ 𝑉 ) |
|
Assertion |
fvmptd4 |
⊢ ( 𝜑 → ( 𝐹 ‘ 𝐴 ) = 𝐶 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
fvmptd4.1 |
⊢ ( 𝑥 = 𝐴 → 𝐵 = 𝐶 ) |
2 |
|
fvmptd4.2 |
⊢ ( 𝜑 → 𝐹 = ( 𝑥 ∈ 𝐷 ↦ 𝐵 ) ) |
3 |
|
fvmptd4.3 |
⊢ ( 𝜑 → 𝐴 ∈ 𝐷 ) |
4 |
|
fvmptd4.4 |
⊢ ( 𝜑 → 𝐶 ∈ 𝑉 ) |
5 |
1
|
adantl |
⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → 𝐵 = 𝐶 ) |
6 |
2 5 3 4
|
fvmptd |
⊢ ( 𝜑 → ( 𝐹 ‘ 𝐴 ) = 𝐶 ) |