Metamath Proof Explorer


Theorem fvmptn

Description: This somewhat non-intuitive theorem tells us the value of its function is the empty set when the class C it would otherwise map to is a proper class. This is a technical lemma that can help eliminate redundant sethood antecedents otherwise required by fvmptg . (Contributed by NM, 21-Oct-2003) (Revised by Mario Carneiro, 9-Sep-2013)

Ref Expression
Hypotheses fvmptn.1 ⊢ ( 𝑥 = 𝐷 → 𝐵 = 𝐶 )
fvmptn.2 ⊢ 𝐹 = ( 𝑥 ∈ 𝐴 ↦ 𝐵 )
Assertion fvmptn ( ¬ 𝐶 ∈ V → ( 𝐹 ‘ 𝐷 ) = ∅ )

Proof

Step Hyp Ref Expression
1 fvmptn.1 ⊢ ( 𝑥 = 𝐷 → 𝐵 = 𝐶 )
2 fvmptn.2 ⊢ 𝐹 = ( 𝑥 ∈ 𝐴 ↦ 𝐵 )
3 nfcv ⊢ Ⅎ 𝑥 𝐷
4 nfcv ⊢ Ⅎ 𝑥 𝐶
5 3 4 1 2 fvmptnf ⊢ ( ¬ 𝐶 ∈ V → ( 𝐹 ‘ 𝐷 ) = ∅ )