Metamath Proof Explorer


Theorem fwfffun

Description: If ps is function-like over A , then F matches its behavior. (Contributed by BTernaryTau, 28-Sep-2026)

Ref Expression
Hypotheses fwfffun.1 ⊢ Ⅎ 𝑦 𝜓
fwfffun.2 ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∃ 𝑦 ∀ 𝑧 ∈ 𝐴 ( 𝜓 → 𝑧 = 𝑦 ) )
fwfffun.3 ⊢ 𝐹 = { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) }
Assertion fwfffun ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑥 ∈ dom 𝐹 ∧ ( 𝐹 ‘ 𝑥 ) = 𝑧 ) ) )

Proof

Step Hyp Ref Expression
1 fwfffun.1 ⊢ Ⅎ 𝑦 𝜓
2 fwfffun.2 ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∃ 𝑦 ∀ 𝑧 ∈ 𝐴 ( 𝜓 → 𝑧 = 𝑦 ) )
3 fwfffun.3 ⊢ 𝐹 = { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) }
4 3 eleq2i ⊢ ( ⟨ 𝑥 , 𝑧 ⟩ ∈ 𝐹 ↔ ⟨ 𝑥 , 𝑧 ⟩ ∈ { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) } )
5 opabidw ⊢ ( ⟨ 𝑥 , 𝑧 ⟩ ∈ { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) } ↔ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) )
6 4 5 bitri ⊢ ( ⟨ 𝑥 , 𝑧 ⟩ ∈ 𝐹 ↔ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) )
7 1 rmo2 ⊢ ( ∃* 𝑧 ∈ 𝐴 𝜓 ↔ ∃ 𝑦 ∀ 𝑧 ∈ 𝐴 ( 𝜓 → 𝑧 = 𝑦 ) )
8 7 ralbii ⊢ ( ∀ 𝑥 ∈ 𝐴 ∃* 𝑧 ∈ 𝐴 𝜓 ↔ ∀ 𝑥 ∈ 𝐴 ∃ 𝑦 ∀ 𝑧 ∈ 𝐴 ( 𝜓 → 𝑧 = 𝑦 ) )
9 2 8 sylibr ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∃* 𝑧 ∈ 𝐴 𝜓 )
10 funopab ⊢ ( Fun { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) } ↔ ∀ 𝑥 ∃* 𝑧 ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) )
11 3 funeqi ⊢ ( Fun 𝐹 ↔ Fun { ⟨ 𝑥 , 𝑧 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) } )
12 2reu5lem2 ⊢ ( ∀ 𝑥 ∈ 𝐴 ∃* 𝑧 ∈ 𝐴 𝜓 ↔ ∀ 𝑥 ∃* 𝑧 ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) )
13 10 11 12 3bitr4i ⊢ ( Fun 𝐹 ↔ ∀ 𝑥 ∈ 𝐴 ∃* 𝑧 ∈ 𝐴 𝜓 )
14 9 13 sylibr ⊢ ( 𝜑 → Fun 𝐹 )
15 df-br ⊢ ( 𝑥 𝐹 𝑧 ↔ ⟨ 𝑥 , 𝑧 ⟩ ∈ 𝐹 )
16 funbrfv2b ⊢ ( Fun 𝐹 → ( 𝑥 𝐹 𝑧 ↔ ( 𝑥 ∈ dom 𝐹 ∧ ( 𝐹 ‘ 𝑥 ) = 𝑧 ) ) )
17 15 16 bitr3id ⊢ ( Fun 𝐹 → ( ⟨ 𝑥 , 𝑧 ⟩ ∈ 𝐹 ↔ ( 𝑥 ∈ dom 𝐹 ∧ ( 𝐹 ‘ 𝑥 ) = 𝑧 ) ) )
18 14 17 syl ⊢ ( 𝜑 → ( ⟨ 𝑥 , 𝑧 ⟩ ∈ 𝐹 ↔ ( 𝑥 ∈ dom 𝐹 ∧ ( 𝐹 ‘ 𝑥 ) = 𝑧 ) ) )
19 6 18 bitr3id ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑥 ∈ dom 𝐹 ∧ ( 𝐹 ‘ 𝑥 ) = 𝑧 ) ) )